I have this retarded problem.

The following code prints all the divisors of input integer n. By adding some lines of code change the program to also print whether or not n is prim. Print the output for each input: 8,31, 56, 57.

def divisor(n):
for i in range(1,n+1,1):
if n%i == 0:
print i

I am an accounting major I don't need to know how to program.

I thought it was worth a shot to post it on here lol.

 

UH, WTF? This must be some specialized stuff because my required general education isn't recognizing. I've had an accounting class though.

 

I'm an Accounting and "information systems" major. So thats why I have to do this

 

looking at your code.

Just my best guess... haven't touched python in a LONG time.

for n in [8, 31, 56, 57]:
for x in range(2, n):
if n % x == 0:
break
else:
# loop finished wtihout finding a factor
print n, 'is a prime number'

 

Does this go back to the "Chinese Arithmetic" thing ?

 

Dude, I have no idea what is going on in here.... Letters and numbers trying to solve some kind of an equation thing.. I'm sorry, letters do not belong in matematical equations. Math = numbers.

Bah!

 

the letters are numbers. Ever heard of pi? It's not filled with fruit.