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Originally Posted by whitethunder46
I understand how the plane will take off. But question, will the plane go the same distance on the conveyor belt when taking off as it would on a normal runway?
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Yep, the conveyor and wheels are irrelevant to thrust
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LoL only mustang tuning would u get 4 pages of forum notes on BS physics and stuff.
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im gunna say yeah, it will be able to take off. like stated, the wheels are free, the speed they are goin at isnt relative to the speed the plane is going. the force thats driving the plane are the jet engines, not a drivetrain to the wheels.
say the plane is goin 5 mph south, and the conveyor belt is goin 5 mph to the north. if a car was driving using the wheels, it would be staying still. because the jets are pushing the plane, it would be moving at 5mph, whereas its wheels would be spinning at 10mph (maybe my math is ****ed up, its 215am and iv had a long day. u get the gist of it though) edit: i didnt see the other 3 pages.... imma go back and read those and see if someone answered! |
lol, I knew the answer, i just wanted to see if I could confuse any of ya'll. It was rather funny reading through that entire thread.
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I have finals starting this weekend..don't make me think about stuff like this lol
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Originally Posted by MahnotinkneeGT
I have finals starting this weekend..don't make me think about stuff like this lol
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...whoever said Mustang owners are dumb... y'all are bunch of regular aerospace engineers! :D
....my phone is ringing, brb.................... It's NASA, the want to start a M-T branch of the space agency....anybody looking for a job? |
The plane need only be able to generate enough lift to get it off the ground(conveyor). Once it does that thrust will take over and get the plane moving(relative to the actual ground), at which time more lift will be created due to pressure differences created by more relative thrust once the plane is moving. The plane is fully capable of taking off because if it weren't generating enough thrust in order to attain take off speed, even though it's on a conveyor/treadmill the treadmill and/or the wheels would be motionless. It's generating it's own "windspeed" with the thrust of the engines while on the conveyors otherwise it wouldn't be moving the conveyor belt.
I say yes... it'll take off like a shot... |
Originally Posted by rada
...whoever said Mustang owners are dumb... y'all are bunch of regular aerospace engineers! :D
....my phone is ringing, brb.................... It's NASA, the want to start a M-T branch of the space agency....anybody looking for a job? |
Originally Posted by caballo
The plane need only be able to generate enough lift to get it off the ground(conveyor). Once it does that thrust will take over and get the plane moving(relative to the actual ground), at which time more lift will be created due to pressure differences created by more relative thrust once the plane is moving. The plane is fully capable of taking off because if it weren't generating enough thrust in order to attain take off speed, even though it's on a conveyor/treadmill the treadmill and/or the wheels would be motionless. It's generating it's own "windspeed" with the thrust of the engines while on the conveyors otherwise it wouldn't be moving the conveyor belt.
I say yes... it'll take off like a shot... you got the right answer but the wrong way of getting to it... |
I got the concept. that's enough for me...
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Originally Posted by Grimmz
LmAo...well Springs is right there outside the USAFA, Class trip to Washington DC to the Air and Space Museum...Tea and Biscuits afterwards!
Springs already hada job offer from NASA.... with that banana-colored car of his, he's been picked up as the next space-chimp! :eek: :D ROFL |
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